The coefficient of static friction, µ S , between block A of mass 2kg and the table as shown in the figure, is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless: (g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
D
Key Idea: The tension in the string is equal to static frictional force between block A and the surface.
Let the mass of the block B is M.
In equilibrium
If blocks do not move then
where 
frictional force 
Thus, from Egs. (i) and (ii), we have
or 
Given: 
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